Op 02.mrt.2025 om 15:42 schreef olcott:
HHH is an emulating termination analyzer that emulates
the x86 machine code located at the address of a function
using a fully functional x86 emulator.
When HHH recognizes a non-terminating pattern in the
execution trace of its emulated input it aborts this
emulation and returns 0.
typedef void (*ptr)();
int HHH(ptr P);
int DD()
{
ÿÿ int Halt_Status = HHH(DD);
ÿÿ if (Halt_Status)
ÿÿÿÿ HERE: goto HERE;
ÿÿ return Halt_Status;
}
_DD()
[00002133] 55ÿÿÿÿÿÿÿÿ push ebpÿÿÿÿÿ ; housekeeping
[00002134] 8becÿÿÿÿÿÿ mov ebp,espÿÿ ; housekeeping
[00002136] 51ÿÿÿÿÿÿÿÿ push ecxÿÿÿÿÿ ; make space for local
[00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404ÿÿÿÿ add esp,+04
[00002144] 8945fcÿÿÿÿ mov [ebp-04],eax
[00002147] 837dfc00ÿÿ cmp dword [ebp-04],+00
[0000214b] 7402ÿÿÿÿÿÿ jz 0000214f
[0000214d] ebfeÿÿÿÿÿÿ jmp 0000214d
[0000214f] 8b45fcÿÿÿÿ mov eax,[ebp-04]
[00002152] 8be5ÿÿÿÿÿÿ mov esp,ebp
[00002154] 5dÿÿÿÿÿÿÿÿ pop ebp
[00002155] c3ÿÿÿÿÿÿÿÿ ret
Size in bytes:(0035) [00002155]
I challenged everyone here to provide the machine address
by machine address (AKA line by line) execution trace
of DD correctly emulated by HHH that reaches its own
"ret" instruction.
Olcott could as well challenge everyone to draw a correct square circle.
No one made any attempt to do this because they know that
this would prove that they are stupidly wrong to say that
my trace is incorrect.
No one will attempt to draw a square circle. Does that imply that it is wrong to say that another failed attempt to draw a square circle is incorrect?
Similarly, HHH cannot possibly simulate itself correctly.
Olcott's HHH
is incorrect, but a correct HHH that simulates itself does not exist. Therefore, it is very stupid to challenge everyone to correct HHH.
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