On Fri, 24 Jul 2026 11:03:09 -0400, micky wrote:
You may have noticed by now that clicking on Google search links
sometimes or always makes you stop at a page to "permit" redirection
to another page, even though you clicked on it in the first place
and even though it never did this before. "The "redirect notice"
page usually appears because Google wraps outbound links with a
tracking parameter (google.com/url) to gather analytics and scan for malicious URLs".
I often copy and paste links into the following script for this reason.
Feel free to experiment with this as appropriate. Note the ?--unquote?
option, because sometimes I find the wrapped URL has an extra
(needless) level of quoting.
----
#!/usr/bin/python3
#+
# Given a URL from various sites that like to include redirection
# capture cruft, extract the URL and discard the cruft.
#-
import sys
import re
from urllib import \
parse as urlparse
import getopt
start_marker = r"\=(https?(\:\/\/|\%3a\%2f\%2f))"
show_original = False
force_unquote = False
opts, args = getopt.getopt \
(
sys.argv[1:],
"",
["original", "unquote"]
)
for keyword, value in opts :
if keyword == "--original" :
show_original = True
elif keyword == "--unquote" :
force_unquote = True
#end if
#end for
urls = args
if len(urls) == 0 :
raise getopt.GetoptError("pass at least one URL to unredirect")
#end if
for url in urls :
matches = list(re.compile(start_marker, re.IGNORECASE).finditer(url))
if len(matches) != 0 :
match = matches[-1]
startpos = match.start(1)
endpos = url.find("&", match.end(1))
if endpos < 0 :
endpos = len(url)
#end if
actual = url[startpos : endpos]
if match.group(2).startswith("%") or force_unquote :
actual = urlparse.unquote(actual)
#end if
if show_original :
sys.stdout.write("%s => " % url)
#end if
sys.stdout.write("%s\n" % actual)
else :
sys.stdout.write("# Cannot understand: %s\n" % url)
#end if
#end for
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